Real Numbers · Mathematics Ch.1 · Class X CBSE · Quick Revision
| Symbol | Set | Examples |
|---|---|---|
| ℕ | Natural Numbers | 1, 2, 3, … |
| 𝕎 | Whole Numbers | 0, 1, 2, 3, … |
| ℤ | Integers | …−2, −1, 0, 1, 2… |
| ℚ | Rational (p/q form) | 3/4, −7, 0.5 |
| ℚ′ | Irrational | √2, √3, π, e |
| ℝ | Real = ℚ ∪ ℚ′ | All of the above |
| When to use HCF | When to use LCM |
|---|---|
| Dividing into equal groups | Events repeating together |
| Max size of equal pieces | Bells ringing simultaneously |
| "Largest number that divides…" | "Smallest number divisible by…" |
| No remainder left over | Synchronising cycles |
| Type | Condition | Example |
|---|---|---|
| Terminating | q = 2ⁿ×5ᵐ only | 3/8=0.375 |
| Non-term. Recurring | q has other primes | 1/3=0.3̄ |
| Non-term. Non-recurring | Irrational number | √2=1.414… |
| Feature | Euclid's Division Algorithm | Prime Factorisation (FTA) |
|---|---|---|
| Finds | HCF only | HCF and LCM both |
| Best for | Large numbers (fewer errors) | Smaller numbers; when LCM is needed |
| Process | Repeated division until remainder = 0 | Factor tree → compare prime powers |
| Three numbers | Apply algorithm twice | All at once: lowest/highest powers |
| Error risk | Low — only division needed | Higher for large numbers |
| Product formula | HCF × LCM = a×b (only 2 numbers) | HCF × LCM = a×b (only 2 numbers) |
| Fraction | Simplified? | Denominator factors | Type | Decimal |
|---|---|---|---|---|
| 3/8 | Yes | 2³ only ✓ | Terminating | 0.375 |
| 7/20 | Yes | 2²×5 only ✓ | Terminating | 0.35 |
| 77/210 | 77/210 = 11/30 | 2×3×5 — has 3 ✗ | Non-term. Recurring | 0.3666… = 0.36̄ |
| 1/6 | Yes | 2×3 — has 3 ✗ | Non-term. Recurring | 0.1666… = 0.16̄ |
| 2/11 | Yes | 11 — prime ✗ | Non-term. Recurring | 0.1818… = 0.1̄8̄ |
| √2 | — | Irrational | Non-term. Non-recurring | 1.41421356… |
| π | — | Irrational | Non-term. Non-recurring | 3.14159265… |
N ⊂ W ⊂ Z ⊂ Q ⊂ R — every subset contains the previous one.
HCF takes the LOWEST (humble) powers of common primes. LCM takes the HIGHEST (large) powers of all primes.
Simplify the fraction fully. If denominator = 2ⁿ × 5ᵐ and nothing else → terminating decimal.
√2 proof key step: assume p/q in lowest terms → p even → q even → HCF ≥ 2. Contradicts lowest terms!
"Dividing / max size / equal groups" → HCF. "Together again / cycles / simultaneous" → LCM.
22/7 ≈ 3.14285 (rational). π ≈ 3.14159 (irrational). 22/7 is only an approximation — both differ after 2 decimal places.
Apply a=bq+r, replace a←b, b←r. When r=0, the last non-zero divisor is the HCF.
Proof: if it were rational, then x = (r+x)−r = rational−rational = rational. Contradiction!