Trigonometry · Mathematics Ch.8 · Class X CBSE · Quick Revision
| θ | 0° | 30° | 45° | 60° | 90° |
|---|---|---|---|---|---|
| sin θ | 0 | 1/2 | 1/√2 | √3/2 | 1 |
| cos θ | 1 | √3/2 | 1/√2 | 1/2 | 0 |
| tan θ | 0 | 1/√3 | 1 | √3 | N.D. |
| cosec θ | N.D. | 2 | √2 | 2/√3 | 1 |
| sec θ | 1 | 2/√3 | √2 | 2 | N.D. |
| cot θ | N.D. | √3 | 1 | 1/√3 | 0 |
| Ratio | Range | Notes |
|---|---|---|
| sin θ | 0 to 1 | Increases: 0→1 |
| cos θ | 1 to 0 | Decreases: 1→0 |
| tan θ | 0 to ∞ | Increases: 0→N.D. |
| cosec θ | ∞ to 1 | cosec θ ≥ 1 |
| sec θ | 1 to ∞ | sec θ ≥ 1 |
| cot θ | ∞ to 0 | Decreases |
| O | A | H | If tan θ = O/A |
|---|---|---|---|
| 3 | 4 | 5 | sin=3/5, cos=4/5 |
| 5 | 12 | 13 | sin=5/13, cos=12/13 |
| 8 | 15 | 17 | sin=8/17, cos=15/17 |
| 7 | 24 | 25 | sin=7/25, cos=24/25 |
sin 0°=√0/2=0, sin 30°=√1/2=1/2, sin 45°=√2/2=1/√2, sin 60°=√3/2, sin 90°=√4/2=1
cos 0°=1, cos 30°=√3/2, cos 45°=1/√2, cos 60°=1/2, cos 90°=0 — exactly reversed!
co-sine = complement's sine. co-tangent = complement's tangent. co-secant = complement's secant.
sin=P/H, cos=B/H, tan=P/B (P=perpendicular, B=base, H=hypotenuse)
Both come from sin²θ+cos²θ=1. One master identity gives you all three!
Use this to quick-check your answers. If sin 60° < sin 30° in your answer, something is wrong.