📋 Cheat Sheet

Trigonometry · Mathematics Ch.8 · Class X CBSE · Quick Revision

📐 Trigonometric Ratios
IN RIGHT △ABC, ∠B = 90°, FOR ANGLE A (= θ)
sin θ = O/H   cos θ = A/H   tan θ = O/A
O = BC (opposite), A = AB (adjacent), H = AC (hypotenuse)
RECIPROCAL RATIOS
cosec θ = H/O   sec θ = H/A   cot θ = A/O
sin·cosec = 1   cos·sec = 1   tan·cot = 1
tan θ = sin θ / cos θ    cot θ = cos θ / sin θ
Mnemonic: SOH-CAH-TOA or "Some People Have Curly Brown Hair Through Proper Brushing"
Hypotenuse is always opposite the 90° angle — it never changes.
📊 Standard Angle Values Table
θ30°45°60°90°
sin θ01/21/√2√3/21
cos θ1√3/21/√21/20
tan θ01/√31√3N.D.
cosec θN.D.2√22/√31
sec θ12/√3√22N.D.
cot θN.D.√311/√30
Memory Trick for sin sin 0°, 30°, 45°, 60°, 90° = √0/2, √1/2, √2/2, √3/2, √4/2.  cos = same in reverse order.  tan = sin ÷ cos.
🔺 Special Triangles
30-60-90 TRIANGLE (half of equilateral △, side 2)
Sides: 1, √3, 2
sin 30°=1/2, cos 30°=√3/2, tan 30°=1/√3
sin 60°=√3/2, cos 60°=1/2, tan 60°=√3
45-45-90 TRIANGLE (isosceles right triangle)
Sides: 1, 1, √2
sin 45° = cos 45° = 1/√2, tan 45° = 1
These two triangles give ALL standard angle values!
🔗 Trigonometric Identities
IDENTITY ① (MASTER IDENTITY)
sin²θ + cos²θ = 1
Proof: Pythagoras → O²+A²=H² → divide by H²
IDENTITY ② (divide ① by cos²θ)
1 + tan²θ = sec²θ
IDENTITY ③ (divide ① by sin²θ)
1 + cot²θ = cosec²θ
Useful: sec²θ − tan²θ = 1 → (secθ−tanθ)(secθ+tanθ) = 1
Useful: cosec²θ − cot²θ = 1 → (cosecθ−cotθ)(cosecθ+cotθ) = 1
🔄 Complementary Angles (A + B = 90°)
COMPLEMENTARY ANGLE FORMULAS
sin(90°−θ) = cos θ    cos(90°−θ) = sin θ
tan(90°−θ) = cot θ    sec(90°−θ) = cosec θ
Each ratio → its "co-" partner. The "co" in cosine = complement's sine.
sin 72° = cos 18°  |  tan 55° = cot 35°  |  sec 80° = cosec 10°
Key result: sin²A + sin²(90°−A) = sin²A + cos²A = 1
📏 Range of Trig Ratios (0° ≤ θ ≤ 90°)
RatioRangeNotes
sin θ0 to 1Increases: 0→1
cos θ1 to 0Decreases: 1→0
tan θ0 to ∞Increases: 0→N.D.
cosec θ∞ to 1cosec θ ≥ 1
sec θ1 to ∞sec θ ≥ 1
cot θ∞ to 0Decreases
Quick Check If your answer gives sin θ = 2 or cos θ = −3 for an acute angle → it's WRONG.
✏️ Strategy for Proving Identities
1.
Start from the more complex side (usually LHS)
2.
Convert everything to sin θ and cos θ
3.
Use sin²θ + cos²θ = 1 to simplify
4.
Factor, combine fractions, rationalise denominators
5.
Never cross the = sign — don't assume the result!
Conjugate trick: Multiply by (secθ+tanθ)/(secθ+tanθ) or (1+sinθ)/(1+sinθ) to simplify.
📝 Worked Examples
Given tan θ = 3/4, find all ratios:
O=3, A=4, H=√(9+16)=5
sin=3/5, cos=4/5, cosec=5/3, sec=5/4, cot=4/3
Evaluate sin 65°/cos 25°:
sin 65° = cos 25° → answer = 1
Prove (1+tan²θ)/(1+cot²θ) = tan²θ:
= sec²θ/cosec²θ = sin²θ/cos²θ = tan²θ ■
sin(A+B)=1, cos(A−B)=√3/2 → find A, B:
A+B=90°, A−B=30° → A=60°, B=30°
⚠️ Common Mistakes to Avoid
sin²θ ≠ sin(θ²) — sin²θ means (sin θ)² i.e. square of sine value
sin(A+B) ≠ sin A + sin B — trig functions are NOT linear!
√(sin²θ + cos²θ) ≠ sin θ + cos θ — √1 = 1, not sin θ + cos θ
tan 90° is undefined, not infinity — division by zero is not defined
1/sin θ = cosec θ, NOT sin⁻¹θ (that's inverse sine — different concept)
🔢 Common Pythagorean Triplets
OAHIf tan θ = O/A
345sin=3/5, cos=4/5
51213sin=5/13, cos=12/13
81517sin=8/17, cos=15/17
72425sin=7/25, cos=24/25
Multiples also work: 6-8-10, 9-12-15, 10-24-26, etc.
🧠 Memory Tricks & Mnemonics
sin Table: "√0, √1, √2, √3, √4 — all over 2"

sin 0°=√0/2=0, sin 30°=√1/2=1/2, sin 45°=√2/2=1/√2, sin 60°=√3/2, sin 90°=√4/2=1

cos = sin in Reverse

cos 0°=1, cos 30°=√3/2, cos 45°=1/√2, cos 60°=1/2, cos 90°=0 — exactly reversed!

"co-" means "complement"

co-sine = complement's sine. co-tangent = complement's tangent. co-secant = complement's secant.

Indian Mnemonic: "Pandit Badri Prasad Har Har Bole"

sin=P/H, cos=B/H, tan=P/B (P=perpendicular, B=base, H=hypotenuse)

Identity Derivation: "Divide by cos² → Identity ②, Divide by sin² → Identity ③"

Both come from sin²θ+cos²θ=1. One master identity gives you all three!

As θ increases (0°→90°): sin ↑, cos ↓, tan ↑

Use this to quick-check your answers. If sin 60° < sin 30° in your answer, something is wrong.