Cheat Sheet ยท CBSE Class X ยท Chapter 10
| Term | Symbol | Meaning |
|---|---|---|
| Pole | P | Centre of mirror surface |
| Centre of Curvature | C | Centre of the sphere |
| Principal Focus | F | Midpoint of P and C |
| Radius of Curvature | R | Distance P โ C |
| Focal Length | f | Distance P โ F |
| Object at | Image at | Nature | Size |
|---|---|---|---|
| โ | F | Real, inv. | Point |
| Beyond C | Between F & C | Real, inv. | Diminished |
| At C | At C | Real, inv. | Same |
| Between C & F | Beyond C | Real, inv. | Enlarged |
| At F | โ | Real, inv. | Very large |
| Between F & P | Behind mirror | Virtual, erect | Enlarged |
u = object distance, v = image distance, f = focal length. All measured from pole P.
m > 0 โ erect (virtual). m < 0 โ inverted (real).
|m| > 1 โ enlarged. |m| < 1 โ diminished.
| Concave Mirror | Convex Mirror |
|---|---|
| Torches, headlights, solar furnaces | Rear-view mirrors in vehicles |
| Shaving / make-up mirrors | Security mirrors in shops |
| Dentist's mirror | Wider field of view |
The ratio sin i / sin r = constant = nโ/nโ = โnโ (refractive index of medium 2 w.r.t. 1).
c = speed in vacuum, v = speed in medium.
| Material | n |
|---|---|
| Air | 1.0003 โ 1 |
| Water | 1.33 |
| Glass | 1.50 โ 1.52 |
| Diamond | 2.42 |
| Object | Image | Nature | Size |
|---|---|---|---|
| โ | Fโ | Real | Point |
| Beyond 2Fโ | Fโ โ 2Fโ | Real | Diminished |
| At 2Fโ | At 2Fโ | Real | Same |
| Fโ โ 2Fโ | Beyond 2Fโ | Real | Enlarged |
| At Fโ | โ | Real | Very large |
| O โ Fโ | Same side | Virtual | Enlarged |
Magnification: m = h'/h = v/u
| Concave M | Convex M | Convex L | Concave L | |
|---|---|---|---|---|
| u | โ | โ | โ | โ |
| f | โ | + | + | โ |
| v (real) | โ | โ | + | โ |
| v (virtual) | + | + | โ | โ |
An object is placed 30 cm from a concave mirror of focal length 15 cm. Find image position and nature.
Solution: u = โ30, f = โ15
v = โ30 cm (real, inverted, same size โ object at C, image at C).
m = โ(โ30)/(โ30) = โ1 โ inverted, same size โ
A convex lens of focal length 20 cm has an object at 30 cm. Find v and m.
Solution: u = โ30, f = +20
v = +60 cm (real, inverted, on the other side).
m = v/u = 60/(โ30) = โ2 โ inverted, 2ร enlarged โ